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Application of Second law of Motion

a car moving ...

Question

a car moving at 40 km/hr is to be stopped by applying brakes in the next 4 m. if the car weighs 2000 kg, what avg force must be applied on it?

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Solution

Finding the deceleration required to stop the car, u = 40kmph=11.11m./s
=v²-u²=2as
=0-(200/18)²=-2a*4
Hence a = 15.42

weight of the car = 2000 N
mass of the car = 2000/9.8 = 204.08 kg

force on the car = 204.08×15.42 = 3146.94 N.

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