a car travelling at a speed of 10 mts / sec is bought to rest in 20 sec by applying brakes. calculate the acceleration and the distance travelled

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Solution

$I n i t i a l s p e e d u = 10 m / s f i n a l s p e e d v = 0 t i m e t a k e n t = 20 s a c c e l e r a t i o n i s a s, a = \frac{v - u}{t} a = \frac{0 - 10}{20} a = - 0.5 m / s^{2} D i s \tan c e t r a v e l l e d : s = u t + \frac{1}{2} a t^{2} s = 10 (20) - \frac{1}{2} \times 0.5 \times 20 \times 20 s = 100 m$

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a car travelling at a speed of 10 mts / sec is bought to rest in 20 sec by applying brakes. calculate the acceleration and the distance travelled

Initial speed u = 10 m/sfinal speed v = 0time taken t = 20 sacceleration is as,a = v-uta =0-1020a = -0.5 m/s2Distance travelled :s = ut + 12at2s = 10(20) - 12×0.5×20×20s = 100 m