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Question

a car travels first half of a length in s with velocity v1. the second half of the length is covered with velocities v2 and v3 for equal time intervals.find the average velocity of the motion.

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Solution

total distance = sfirst half is travelled with velocity v1 in tme t1v1 = s/2t1t1 = s2v1secong half is travelled with v2 and v3 in equla time say t.v2 = s2tv3 = s3ts2+s3 = s2v2t+v3t = s2(v2+v3)t = s2t = s2(v2+v3)average velocity = net displacementtotal timeV =st1+t+tV = s s2v1+2s2(v2+v3)V = 2v1(v2+v3)2v1+v2+v3

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