Question

A closed container contains one mole of nitrogen gas at temperature T and pressure P. Another identical vessel contains two moles of hydrogen gas at temperature 3T. Its pressure will be

Answer 1

$$\begin{gathered} WeknowPV=nRT \\ Incaseofgivenconditions, \\ \frac{P_1}{P_2}=\frac{n_1{T}_1}{n_2{T}_2} \\ So\frac{P}{P_2}=\frac{1\times T}{2\times 3\times T} \\ or{P}_2=6P \\ Thereforetherequiredpressureis6P. \end{gathered}$$