a constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at 0 degree celcius and 100 degree celcius respectively. When the pressure reading is 60 cm of mercury, what will be the temperature?

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Solution

We know, when V is constant, P is proportional to T.
P = AT + B
When T = 0, P = 50 cm of mercury
=> 50 = 0 + B
=> B = 50
When T = 100, P = 90 cm of mercury
=> 90 = 100A + 50
=> A = 0.4
Now, when P = 60 cm of mercury
P = AT + B
=> 60 = (0.4)(T) + 50
=> T = 10/0.4 = 25 ^oC

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a constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at 0 degree celcius and 100 degree celcius respectively. When the pressure reading is 60 cm of mercury, what will be the temperature?

We know, when V is constant, P is proportional to T.P = AT + BWhen T = 0, P = 50 cm of mercury=> 50 = 0 + B=> B = 50When T = 100, P = 90 cm of mercury=> 90 = 100A + 50=> A = 0.4Now, when P = 60 cm of mercuryP = AT + B=> 60 = (0.4)(T) + 50=> T = 10/0.4 = 25 oC

We know, when V is constant, P is proportional to T.
P = AT + B
When T = 0, P = 50 cm of mercury
=> 50 = 0 + B
=> B = 50
When T = 100, P = 90 cm of mercury
=> 90 = 100A + 50
=> A = 0.4
Now, when P = 60 cm of mercury
P = AT + B
=> 60 = (0.4)(T) + 50
=> T = 10/0.4 = 25 ^oC