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Question

a convex lens of focal lenght 10 cm is placed xoaxiaaly 5cm away from a concave lens of foacl length 10cm if the object is placed 30cm in front of the convex lens. find the position of the final image formed by the combines series.

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Solution

f= 10 cmu = -30 cm 1/f = 1/v-1/u1/10 = 1/v+1/30v=15 cm wrt to convex lens. u for the concave lens = 15 - 5 = 10 cmnow for concave lens:1/f= 1/v-1/u 1/-10 =1/v - 1/10v=

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