A copper wire has diameter 00.5mm and resistivity of 1,6x10.8m. What will be the length of this wire to make its resistance 10 ohm. How does the resistance change if the diameter is doubled.

Open in App

Solution

Here,

Diameter, d = 0.5 mm = 0.0005 m

Resistivity, q = 1×10^-8 Ωm

Resistance, R = 10 Ω

Length = L

Now,

R = qL/A

=> L = AR/q

=> L = (πd²/4)R/q

=> L = (3.14×0.0005²/4)(10)/(1×10^-8)

=> L = 196.25 m

If diameter is doubled resistance becomes half.

Regards

Suggest Corrections

Similar questions

1.A copper wire has diameter 0.5mm & reactivity of 1.6*10 to the power -8 ohm m.what will be the length of this wire to make its resistance 10 ohm ? How much does the resistance charge if the diameter is doubled?

Join BYJU'S Learning Program

A copper wire has diameter 00.5mm and resistivity of 1,6x10.8m. What will be the length of this wire to make its resistance 10 ohm. How does the resistance change if the diameter is doubled.

Here, Diameter, d = 0.5 mm = 0.0005 m Resistivity, q = 1×10-8 Ωm Resistance, R = 10 Ω Length = L Now, R = qL/A => L = AR/q => L = (πd2/4)R/q => L = (3.14×0.00052/4)(10)/(1×10-8) => L = 196.25 m If diameter is doubled resistance becomes half. Regards

Here,

Diameter, d = 0.5 mm = 0.0005 m

Resistivity, q = 1×10^-8 Ωm

Resistance, R = 10 Ω

Length = L

Now,

R = qL/A

=> L = AR/q

=> L = (πd²/4)R/q

=> L = (3.14×0.0005²/4)(10)/(1×10^-8)

=> L = 196.25 m

If diameter is doubled resistance becomes half.

Regards