Question

a cricketer can throw a ball to maximum horizontal distance of 100 m . how high above the ground , can a cricketer throw the same ball

Answer 1

the maximum horizontal range is given as

R = u²sin2θ / g

here,

θ = 45

so,

R = u²/g = 100m

so,

u² = 100xg = 1000

thus,

u = 31.6 m/s

and

the maximum height will be

H = u²/2g

or

= 1000 / 2x10

thus,

H = 50 m