A cross was made between two pure breeding pea plants exhibitting following traits-white flower with smooth seeds and purple flower with wrinkled seeds.What will be the genotype and phenotype between F1 and F2?

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Solution

The phenotypic ratio will be 9:3:3:1
The genotypic ratio will be 4:2: 2: 2: 2:1 :1 :1 :1

If we consider a dihybrid cross with characters YR, Yr, yR and yr as well, the frequency will be as follows:

YR
Yr
yR
yr

YR
YYRR
YYRr
YyRR
YyRr

Yr
YYRr
YYrr
YyRr
Yyrr

yR
YyRR
YyRr
yyRR
yyRr

yr
YyRr
Yyrr
yyRr
yyrr

Here, the phynotypic characters are YR, Yr, yR and yr whose ratio will be 9:3:3:1.

The gynotypic characters are YYRR, YYRr, YYrr, YyRr, YyRR, Yyrr, yyRR, yyRr and yyrr whose ratio are
YyRr 4
yyRr 2
Yyrr 2
YyRR 2
YYRr 2
YYRR 1
yyrr 1
YYrr 1
yyRR 1

Hence, from this data we can conclude that’ the genotypic ratio of a dihybrid cross is 4 : 2 : 2 : 2 : 2 : 1 : 1 : 1 : 1’.

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	YR	Yr	yR	yr
YR	YYRR	YYRr	YyRR	YyRr
Yr	YYRr	YYrr	YyRr	Yyrr
yR	YyRR	YyRr	yyRR	yyRr
yr	YyRr	Yyrr	yyRr	yyrr