Question

a cubical vessel of height 1m is full of water.ehat is the work done in pumping water out of the vessel

Answer 1

The work done in pumping the water out of the vessel will be equal to the potential energy stored in the water,i.e.,

W = mgh

W = m×9.8×1
W = 9.8×m

m = volume × density
m = 1m³ × 1000 Kg/m³
m=1000 Kg

Therefore work done,

W = 9.8×1000
W = 9800 J