Question

a dog initially running at a speed of 2m/s, accelerates at a constant rate of 1.5m/s² for 5s. Calculate (i) the distance covered by the dog from its initial position, (ii) the final velocity of the dog

Answer 1

initial speed u = 2 m/s
time taken t = 5 s
Accelertation a = 1.5 m/s²

$$\begin{gathered} Dis\tan cetravelled \\ s=ut+\frac{1}{2}a{t}^2 \\ s=2\times 5+\frac{1}{2}\times 1.5\times 5\times 5 \\ s=28.75m \\ Finalvelocity \\ v=u+at \\ v=2+1.5\times 5 \\ v=9.5m/s \end{gathered}$$