Question

A. Find the simple interest and the amount on rs1200 for 2 years at 12% p.a.

B.Find the simple interest when Rs360 is deposited for 2 years at 8% p.a.

Answer 1

$$\begin{gathered} \left(\mathrm{A}\right). \\ \mathrm{Principal},\mathrm{P}=\mathrm{Rs}1200 \\ \mathrm{Time},\mathrm{T}=2\mathrm{yrs} \\ \mathrm{Rate},\mathrm{R}=12\%\mathrm{p}.\mathrm{a}. \\ \mathrm{Interest}=\frac{\mathrm{P}\times \mathrm{R}\times \mathrm{T}}{100}=\frac{1200\times 12\times 2}{100}=\mathrm{Rs}288 \\ \mathrm{Now},\mathrm{amount}=\mathrm{P}+\mathrm{I}=1200+288=\mathrm{Rs}1488 \\ \left(\mathrm{B}\right). \\ \mathrm{Principal},\mathrm{P}=\mathrm{Rs}360 \\ \mathrm{Rate},\mathrm{R}=8\%\mathrm{p}.\mathrm{a}. \\ \mathrm{Time},\mathrm{n}=2\mathrm{yrs} \\ \mathrm{Interest}=\frac{\mathrm{P}\times \mathrm{R}\times \mathrm{T}}{100}=\frac{360\times 8\times 2}{100}=\mathrm{Rs}57.60 \end{gathered}$$