Question

A force of 10 kgf is applied on a body of mass 100g initially at rest for 0.1 s. Calculate: (i) the momentum acquired by the body (ii) the distance travelled by the body in 0.1s. (Take g=10 N kg-1)

Answer 1

Force applied, F = 10 kgf = 10×10 = 100 N

Mass, m = 100 g = 0.1 kg

Acceleration, a = F/m = 100/0.1 = 1000 m/s²

Velocity after 0.1 s is,

v = u + at

=> v = 0 + 1000×0.1

=> v = 100 m/s²

So, momentum after 0.1 s is, P = mv = 0.1 × 100 = 10 Ns

2.

Using, S = ut + ½ at²

=> S = 0 + ½ × 1000 × 0.1²

=> S = 5 m