Question

a force of 400N acts on a surface area of 2559.calculate thurst and pressure .calculate the changed pressure of the force how is it made to 600N

Answer 1

Solution:

Given values:

Force, F = 400 N;
Surface Area, A = 2559 m²;
Thrust = ?
Pressure, P = ?

The force acting on an object perpendicular to the surface is called thrust. So, the thrust is 400N

Then,

$$\begin{gathered} Pressure=\frac{Thrust}{Area} \\ P\hspace{0.17em}=\frac{400}{2559} \\ \mathit{P}\mathbf{\hspace{0.17em}}\mathbf{=}\mathbf{}\mathbf{0}\mathbf{.}\mathbf{156}\mathbf{}\mathit{N}\mathbf{/}{\mathit{m}}^{\mathbf{2}} \\ If,Forceis600N\hspace{0.17em}thenthepressureis: \\ Pressure=\frac{600}{2559} \\ \mathit{P}\mathbf{\hspace{0.17em}}\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{2345}\mathbf{}\mathit{N}\mathbf{/}{\mathit{m}}^{\mathbf{2}} \end{gathered}$$