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Question
A gas is enclosed in a vessel at standard temperature.At what temperature volume of enclosed gas will be 1/5 of its initial volume.given that pressure remains constant.
A gas is enclosed in a vessel at standard temperature.At what temperature volume of enclosed gas will be 1/5 of its initial volume.given that pressure remains constant.
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Solution
According to Charle's Law : For a fixed mass of gas at constant pressure (P) ,the volume is directly proportional to the kelvin temperature (T).
V ∝ T
Or, T1 /T2 = V1 /V2
Let T1 is the standard temperature and V1 is the volume occupied by gas at standard temperature.Therefore,
T1 = 273 K
V1= 22.4 L (volume occupied by any gas at STP is 22.4 L)
T2 = ?
V2 = 22.4 L/5 = 4.48 L
T2 = T1 / V1 x V2
= 273 K/ 22.4 L x 4.48 L
= 54.6 K
According to Charle's Law : For a fixed mass of gas at constant pressure (P) ,the volume is directly proportional to the kelvin temperature (T).
V ∝ T
Or, T1 /T2 = V1 /V2
T1 = 273 K
V1= 22.4 L (volume occupied by any gas at STP is 22.4 L)
T2 = ?
V2 = 22.4 L/5 = 4.48 L
T2 = T1 / V1 x V2
= 273 K/ 22.4 L x 4.48 L
= 54.6 K
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