Question

A glass jar contains 6 red, 5 green, 8 blue and 3 yellow marbles. If a single marble choosen at random from a jar, find the probability of choosing

A) red marble

B) green marble

C) blue marble

D) yellow marble.

Answer 1

$$\begin{gathered} \mathrm{No}.\mathrm{of}\mathrm{red}\mathrm{marbles}=6 \\ \mathrm{No}.\mathrm{of}\mathrm{green}\mathrm{marbles}=5 \\ \mathrm{No}.\mathrm{of}\mathrm{blue}\mathrm{marbles}=8 \\ \mathrm{No}.\mathrm{of}\mathrm{Yellow}\mathrm{marbles}=3 \\ \mathrm{Total}\mathrm{no}.\mathrm{of}\mathrm{marbles}=22 \\ \left(1\right). \\ \mathrm{Probability}\mathrm{of}\mathrm{drawing}\mathrm{a}\mathrm{red}\mathrm{marble}=\frac{\mathrm{No}.\mathrm{of}\mathrm{red}\mathrm{marbles}}{\mathrm{Total}\mathrm{no}.\mathrm{of}\mathrm{marbles}}=\frac{6}{22}=\frac{3}{11} \\ \left(2\right). \\ \mathrm{Probability}\mathrm{of}\mathrm{drawing}\mathrm{a}\mathrm{green}\mathrm{marble}=\frac{\mathrm{No}.\mathrm{of}\mathrm{green}\mathrm{marbles}}{\mathrm{Total}\mathrm{no}.\mathrm{of}\mathrm{marbles}}=\frac{5}{22} \\ \left(3\right). \\ \mathrm{Probability}\mathrm{of}\mathrm{drawing}\mathrm{a}\mathrm{blue}\mathrm{marble}=\frac{\mathrm{No}.\mathrm{of}\mathrm{blue}\mathrm{marbles}}{\mathrm{Total}\mathrm{no}.\mathrm{of}\mathrm{marbles}}=\frac{8}{22}=\frac{4}{11} \\ \left(4\right). \\ \mathrm{Probability}\mathrm{of}\mathrm{drawing}\mathrm{a}\mathrm{yellow}\mathrm{marblel}=\frac{\mathrm{No}.\mathrm{of}\mathrm{yellow}\mathrm{marbles}}{\mathrm{Total}\mathrm{no}.\mathrm{of}\mathrm{marbles}}=\frac{3}{22} \end{gathered}$$