a heater coil connected to a 220 v has a resistance of 150 ohms how long will it take for this coil to heat 1 kg from 20deg c to 60deg c assuming that all the heat is taken up by water
Heat produced per second or the power of the heater coil is, P = V2/R = 2202/150 = 322.67 W
Specific heat of water is, S = 4186 j/kg
So, heat required to raise the temperature of 1 kg water from 20 oC to 60 oC is,
H = mSθ = (1)(4186)(60 - 20) = 167440 J
So, time taken is found as,
H = Pt
=> t = H/P = 518.92 J