Question

If 3.42 gram of sucrose is dissolved in 18 gram of water ,then what is the number of oxygen atoms in the solution ?

Answer 1

: C₁₂H₂₂O₁₁ + H₂O → 2C₆H₁₂O₆

3.42 gm 18gm

0.1mole 1mole

0.1 mole of sucrose contain = 0.1 x 6.023 x 10²³ sucrose molecules = 11 x 0.6023 x 10²³ oxygen atoms

1 mole of water contain = 6.023 x 10²³ water molecules = 1 x 6.023 x 10²³ oxygen atoms

Total number of oxygen atoms = 11 x 0.6023 x 10²³ + 1 x 6.023 x 10²³ = 12.6483 x 10²³ atoms.