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Solution

: C12H22O11 + H2O → 2C6H12O6

3.42 gm 18gm

0.1mole 1mole

0.1 mole of sucrose contain = 0.1 x 6.023 x 1023 sucrose molecules = 11 x 0.6023 x 1023 oxygen atoms

1 mole of water contain = 6.023 x 1023 water molecules = 1 x 6.023 x 1023 oxygen atoms

Total number of oxygen atoms = 11 x 0.6023 x 1023 + 1 x 6.023 x 1023 = 12.6483 x 1023 atoms.


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