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Question

a lift performs first part of uts ascent with uniform acceleration 'a' and the remaining with unform retardation '2a'.if 't' is the time of ascent ,find depth of shaft.

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Solution

t1=va,t2=v2aadding t1 and t2 we gett=3v2at=32a×2htat2=3h,h=at23

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