a man divides rs(7x^2y+4y)among his two sons. if one of them gets rs(5x^3+2y-4),how much does the other one gets?
Total money = Rs. (7x2y + 4y)
If one of the sons gets Rs. (5x3 + 2y - 4)
Then the other one will get Rs. [(7x2y + 4y) - (5x3 + 2y - 4)]
Therefore,
=(7x2y + 4y) - (5x3 + 2y - 4)
= 7x2y + 4y - 5x3 - 2y + 4
= 7x2y - 5x3 + 2y + 4
Hence the second son will get Rs. (7x2y - 5x3 + 2y + 4).