Question

a man divides rs(7x^2y+4y)among his two sons. if one of them gets rs(5x^3+2y-4),how much does the other one gets?

Answer 1

Total money = Rs. (7x²y + 4y)

If one of the sons gets Rs. (5x³ + 2y - 4)

Then the other one will get Rs. [(7x²y + 4y) - (5x³ + 2y - 4)]

Therefore,

=(7x²y + 4y) - (5x³ + 2y - 4)

= 7x²y + 4y - 5x³ - 2y + 4

= 7x²y - 5x³ + 2y + 4

Hence the second son will get Rs. (7x²y - 5x³ + 2y + 4).