Question

A mass of 10 kg is dropped from a height of 50 cm.FInd its:

(1.) Potential energy just before dropping

(2.) Kinetic energy just on touching the ground

(3.) Velocity with which it its the ground.(Given:g is equal to 10 m per s)

Answer 1

(1) Its potential energy at the top would be

P = mgh

or

P = 10 X 10 X 0.5

thus,

P = 50 J

(2) Its kinetic energy at bottom would be

KE = PE at the top

so,

KE = 50J

(3) Ot velocity would be

v² = 2KE/m

or

v = (2X50 / 10)^1/2

thus,

v = 3.16 m/s