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Question

A mass of lead is embedded in a block of alumnium(2mm thick). Radiations from a radioactive source incident on the side of the block produce a shadow on a fluroscent screen placed beyond the block. The shadow of the block of aluminium is fainter than the shadow of the lead.

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Solution

We know that Radiation is of three types, Alpha, beta and gamma. Of these three radiations, Gamma rays penetrate the most. Alpha rays emit Alpha particles which can be stopped by using paper. We are aware of the gold foil experiment. Aluminium is also sometimes used instead of gold for this experiment.

Now, lead is a very dense element. It is often used to stop the most penetrating gamma radiations. This effect is called shielding. When Aluminium is embedded inside a lead chamber and the sructure is exposed to radiation, since lead is absorbing material and blocks the radiation to pass through it to some extent, the shadow of the lead is more dark as compared of the shadow of aluminium which allows most of the radiation to pas through.

Here we are using the basic principle of light/radiation where a shadow of an object is formed when it blocks the ray of light (opaque) whereas glass is transparent as it allows radiation to pass through.


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