A metal cube of side 5cm at 28C on heating to 578C increases by 0.15cm.Calculate the coefficient of linear superficial and linear expansion.
Given that:
L=5cm.,ΔL =0.15cm
ΔT=578-28=550 oC
Using ΔL = αLΔT
Coefficient of linear expansion,α=ΔL / LΔT= 0.15/ (5 x 550)=0.0000545 â°C-1
Now,
the relation between the coefficients of linear (αl) and superficial expansion (αa) is
αa = 2αl
=2 x 0.0000545=0.0001091â°C-1