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Question

A metal cube of side 5cm at 28C on heating to 578C increases by 0.15cm.Calculate the coefficient of linear superficial and linear expansion.

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Solution

Given that:

L=5cm.,ΔL =0.15cm

ΔT=578-28=550 oC

Using ΔL = αLΔT

Coefficient of linear expansion,α=ΔL / LΔT= 0.15/ (5 x 550)=0.0000545 ⁰C-1

Now,

the relation between the coefficients of linear (αl) and superficial expansion (αa) is

αa = 2αl

=2 x 0.0000545=0.0001091⁰C-1


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