Question

A pair of fair, standard dice are rolled. What is the probability the sum of the dice is 5?

Answer 1

When two dice are rolled then total possible outcomes are : 6 $\times$ 6 = 36
Favorable cases : {(1, 4) ; (2, 3); (3, 2); (4, 1)}
No. of favorable outcomes = 4
$\mathrm{required}\mathrm{probability}=\frac{\mathrm{no}.\mathrm{of}\mathrm{favorable}\mathrm{outcomes}}{\mathrm{total}\mathrm{possible}\mathrm{outcomes}}=\frac{4}{36}=\frac{1}{9}$