MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Rotation and Revolution of the Moon

A person weig...

Question

A person weighing 60kg is standing in a lift which is moving upwards with accelerarion 4.9 m /s^2 . Find the apparent weight of the person.

Open in App

Solution

Given, a = 4.9m/s²
m = 60kg
Now weight = m g
apparent weight, w = m (g+a) N [because lift is moving upwards]
= 60 (9.8+4.9)
= 882 N

Suggest Corrections

thumbs-up

0

Similar questions

Q. A person of mass

50 k g

is standing in lift. What weight will he experience if the lift is moving upwards with acceleration

2 m / s^{2}

Q. The apparent weight of a person in a lift moving downwards is half his apparent weight in the same lift moving upwards with the same magnitude of acceleration. Acceleration of the lift is:

Q. A person weighing

60 k g

stands on a platform which oscillates up and down at a frequency of

2 H z

5 c m

. The maximum and minimum apparent weights are nearly: (

g

m / s^{2}

)

Q. A person stands on a weighing machine kept on the floor of an elevator, if the elevator moves upward with a constant acceleration, the apparent weight of the person

Q. A person of mass m is in a lift which is accelerating upwards with an acceleration a. His apparent weight is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Rotation and Revolution of Moon

PHYSICS

Watch in App

explore_more_icon

Explore more

Rotation and Revolution of the Moon

Standard VI Physics

Join BYJU'S Learning Program

CrossIcon