A piece of stone of mass 113 g is immersed in a measuring cylinder. The stone sinks to the bottom and the water level in the measuring cylinder rises from 30 cm³ to 40 cm³. Calculate R.D. of stone.

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Solution

Volume of the body = (40 - 30) = 10 cm³
V = 10 cm³
Let Ï be the density of the stone.
m = VÏ
Ï = m/V = 113 / 10 = 11.3 g/ cm³
R.D. = density of the body / density of the water = 11.3/1 = 11.3 g/ cm³

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A piece of stone of mass 113 g is immersed in a measuring cylinder. The stone sinks to the bottom and the water level in the measuring cylinder rises from 30 cm3 to 40 cm3. Calculate R.D. of stone.

Volume of the body = (40 - 30) = 10 cm3V = 10 cm3 Let Ï be the density of the stone.m = VÏÏ = m/V = 113 / 10 = 11.3 g/ cm3R.D. = density of the body / density of the water = 11.3/1 = 11.3 g/ cm3

A piece of stone of mass 113 g is immersed in a measuring cylinder. The stone sinks to the bottom and the water level in the measuring cylinder rises from 30 cm³ to 40 cm³. Calculate R.D. of stone.

Volume of the body = (40 - 30) = 10 cm³
V = 10 cm³
Let Ï be the density of the stone.
m = VÏ
Ï = m/V = 113 / 10 = 11.3 g/ cm³
R.D. = density of the body / density of the water = 11.3/1 = 11.3 g/ cm³