A PINCH OF SODIUM CARBONATE IS ADDED TO 5ml OF PURE WATER. What change can be observed if red litmus paper is dipped into this solution? Why ?

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Solution

When sodium carbonate is added to water, water become basic, because of production of OH^-.
Na₂CO₃ + H₂O = NaOH + H₂CO₃
NaOH = Na⁺ + OH^-

Thus if you insert a red litmus paper (indicator) inside it, it will become blue.

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What happens when [5 MARKS]

a) A red litmus paper is dipped in a solution of calcium hydroxide.

b) A red litmus paper is dipped in a solution of sodium chloride.

c) A blue litmus paper is dipped in lemon juice.

d) A red litmus paper is dipped in distilled water.

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What is observed when neutral litmus solution is added to sodium hydrogen carbonate solution?

A student prepared 20% sodium hydroxide solution in a beaker to study saponification reaction. Some observations related to this are given below:

(I) Sodium hydroxide solution turns red litmus blue
(II) Sodium hydroxide readily dissolves in water
(III) The beaker containing solution appears cold when touched from outside
(IV) The blue litmus paper turns red when dipped into the solution

The correct observations are :

When blue litmus paper is dipped into the water, the colour of litmus paper remains same. Similarly, when a red litmus paper is dipped into the water, the colour remains same. By the above observation, we can conclude that:

When a red litmus paper is dipped in the aqueous solution of $X$ there is no change in colour.
When a blue litmus paper is dipped in the same solution it turns red.
Which among the following options can be the chemical $X$ ?

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A PINCH OF SODIUM CARBONATE IS ADDED TO 5ml OF PURE WATER. What change can be observed if red litmus paper is dipped into this solution? Why ?

When sodium carbonate is added to water, water become basic, because of production of OH-. Na2CO3 + H2O = NaOH + H2CO3 NaOH = Na+ + OH- Thus if you insert a red litmus paper (indicator) inside it, it will become blue.

When sodium carbonate is added to water, water become basic, because of production of OH^-.
Na₂CO₃ + H₂O = NaOH + H₂CO₃
NaOH = Na⁺ + OH^-

Thus if you insert a red litmus paper (indicator) inside it, it will become blue.