Question

A point moves in a straight line so that its displacement 'x' metre at a time 't' second is such that t=square root of (x2-1).The acceleration in m/s2 at time 't' second is

Answer 1

$$\begin{gathered} t=\sqrt{x^2-1} \\ so, \\ x=t^2+1 \\ \frac{dx}{dt}=2t \\ \frac{d^{2}x}{d{t}^2}=2m/s^2=a \end{gathered}$$