A positron is emitted from 11Na23 - what is the ratio of atomic mass and atomic no- of resulting nuclide-

The emission of positron from 11Na23: 11Na23 nbsp; rarr; 10X23 + 1 #946;0 Therefore, nbsp;the ratio of atomic mass and atomic no. of resulting nucl ...

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Standard XII

Chemistry

Concentration Terms

a positron is...

Question

a positron is emitted from ₁₁Na²³ . what is the ratio of atomic mass and atomic no. of resulting nuclide?

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Solution

The emission of positron from ₁₁Na²³:
₁₁Na²³→ ₁₀X²³+ ₁ $β$ ⁰

Therefore, the ratio of atomic mass and atomic no. of resulting nuclide = 23:10

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a positron is emitted from 11Na23 . what is the ratio of atomic mass and atomic no. of resulting nuclide?

The emission of positron from 11Na23: 11Na23 →​ 10X23 + 1β0 Therefore, the ratio of atomic mass and atomic no. of resulting nuclide = 23:10

a positron is emitted from ₁₁Na²³ . what is the ratio of atomic mass and atomic no. of resulting nuclide?

The emission of positron from ₁₁Na²³:
₁₁Na²³→ ₁₀X²³+ ₁ $β$ ⁰

Therefore, the ratio of atomic mass and atomic no. of resulting nuclide = 23:10