A positron is emitted from 11Na23 - what is the ratio of atomic mass and atomic no- of resulting nuclide-

The emission of positron from 11Na23: 11Na23 nbsp; rarr; 10X23 + 1 #946;0 Therefore, nbsp;the ratio of atomic mass and atomic no. of resulting nucl ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Concentration Terms

a positron is...

Question

a positron is emitted from ₁₁Na²³ . what is the ratio of atomic mass and atomic no. of resulting nuclide?

Open in App

Solution

The emission of positron from ₁₁Na²³:
₁₁Na²³→ ₁₀X²³+ ₁ $β$ ⁰

Therefore, the ratio of atomic mass and atomic no. of resulting nuclide = 23:10

Suggest Corrections

Similar questions

Q. A positron is emitted from

_{11}^{23} N a

. The ratio of the atomic mass and atomic number of the resulting nuclide is:

Q. A positron is emitted from

_{11}^{23} N a

. The ratio of the atomic mass and atomic number of the resulting nuclide is:

Q. What is the nuclear process that results in no change in the mass number and atomic number of a nuclide ?

Q. _____________ is a nuclear process that results in no change in the mass number and the atomic number of a nuclide.

Q. An artificial transmutation was carried out on

_{7}^{14} N

by an

α

-particle which resulted in an unstable nuclide and a proton. What is the ratio of the atomic mass to the atomic number of the unstable nuclide?

Join BYJU'S Learning Program

a positron is emitted from 11Na23 . what is the ratio of atomic mass and atomic no. of resulting nuclide?

The emission of positron from 11Na23: 11Na23 →​ 10X23 + 1β0 Therefore, the ratio of atomic mass and atomic no. of resulting nuclide = 23:10

a positron is emitted from ₁₁Na²³ . what is the ratio of atomic mass and atomic no. of resulting nuclide?

The emission of positron from ₁₁Na²³:
₁₁Na²³→ ₁₀X²³+ ₁ $β$ ⁰

Therefore, the ratio of atomic mass and atomic no. of resulting nuclide = 23:10