A ray of light is incident on a glass slab of reflective index 1.5 making an angle 40 with the surface. Find (a) the angle of reflection in glass; (b) speed of light in glass.
Open in App
Solution
According to snell’s law N1sin(i) = N2 sin(r) Sin(40) = 1.5 sin(r) r = 25.32 degree N2= speed of light in air / speed of light in the medium C’ = 3*108/1.5 C’ = 2*108 m/s