a ray of light passing through a equilateral prism suffers minimum deviation . If the angle of minimum deviation is 48, what must be the angle of incidence?

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Solution

We can calculate the angle of incident by using the relation $i = \frac{A + δ_{m}}{2}$
$δ_{m} a n g l e o f m i n i m u m d e v i a t i o n A a n g l e o f p r i s m i n c a s e o f e q u i l a t e r a l t r i a n g l e i t i s e q u a l t o 60^{o} p u t t i n g t h e g i v e n v a l u e s i n t h e a b o v e r e l a t i o n i = \frac{60^{o} + 48^{o}}{2} = 54^{o}$

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What should be the angle of incidence for a ray of light which suffers a minimum deviation of $36^{\circ}$ through an equilateral prism?

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