A rocket is moving up with velocity "v". if the velocity of the rocket is tripled, what will be the ratio of two kinectic energies??
Let, m be the mass of rocket.
Initial kinetic energy is, KEi = ½ mv2
Final kinetic energy is, KEf = ½ m(3v)2 = 9 KEi
Therefore, KEi : KEf = 1 : 9