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Work by Multiple Forces

a rod of mass...

Question

a rod of mass m & length l is lying on a horizontal table work done in making it stand on one end will be?

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Solution

work done = change in potential energy
center of mass of the rod is at the mid point and when the rod is lying horizontally it potential energy is zero.
when it stand on one end the center of mass is at height h= L/2
work done=mgh=mg(L/2)

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