A simple pendulum is oscillating in between the vertical plates of a capacitor having a field E. If mass & charge on the bob are 'm' & 'q' respectively find its time period.
When a charged particle of charge q is placed in an electric field of strength E,
the force experienced by the charged particle = Eq
The acceleration of the charged particle in the electric field,
ma = Eq
When a charged particle of mass m and charge q remains suspended in an vertical electric field then
mg=Eq
When a charged particle of mass m and charge q remains suspended in an electric field, the number of
fundamental charges on the charged particle is n then
mg = E(ne)
n =mg/Ee
The bob of a simple pendulum is given +ve charge and it is made to oscillate in vertically upward electric
field, then the time period of oscillation is
T =2π√ l/(g – Eq/m)