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Question

A simple pendulum is oscillating in between the vertical plates of a capacitor having a field E. If mass & charge on the bob are 'm' & 'q' respectively find its time period.

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Solution

When a charged particle of charge q is placed in an electric field of strength E,

the force experienced by the charged particle = Eq

The acceleration of the charged particle in the electric field,

ma = Eq

When a charged particle of mass m and charge q remains suspended in an vertical electric field then

mg=Eq

When a charged particle of mass m and charge q remains suspended in an electric field, the number of

fundamental charges on the charged particle is n then

mg = E(ne)

n =mg/Ee

The bob of a simple pendulum is given +ve charge and it is made to oscillate in vertically upward electric

field, then the time period of oscillation is

T =2π√ l/(g – Eq/m)


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