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Laws of Definite Proportions, Multiple Proportions

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A solution is prepared by dissolving 11g glucose in 200 cm³ water at 30⁰c. What is the mass percentage of glucose in solution ? The density of water at 30⁰c is 0.996g /cm³?

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Solution

Dear student!
Here, mass of water(solvent) = volume x density = 200 x 0.996 = 199.2 gm
Mass of solute (glucose) = 11 gm
So, mass of solution = 199.2 + 11 = 210.2
Mass %age of solute =( mass of solute / mass of solution) x 100
So, mass %age of glucose = (11/210.2) x 100 = 5.2 %

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