Question

A sound wave of wavelength 0.332 m has a time period of 10^-3 s. If the time period is decreased to 10^-4 s, calculate the wavelength and frequency of the new wave.

Answer 1

Here,

T₁ = 10^-3 s

ν₁ = 1/10^-3 = 10³ Hz

T₂ = 10^-4 s

Frequency of the new wave ν₂ = 1/T₂

= 1/10^-4 = 10⁴ Hz

λ = 0.332 m

Velocity = ν₁ λ

= 0.332 × 10³ = 332 ms^-1

Velocity now is independent of frequency so,

V = λ₂ ν₂

=> 332 = λ₂ × 10⁴

=> λ₂ = 332×10^-4 m