A starter motor of the car draws a current i=300A from the battery of voltage 12V. If the car starts only after 12min, what is the energy drawn from the battery.
we know that
Energy = Power x time
or
E = P x t
here,
t = 12min = 12 x 60 = 720 s
P = VI
where
V = 12 volts
I = 300 amps
so,
P = 12 x 300
thus,
P = 3600 W
now,
the energy drawn from the battery will be
E = 3600 x 720
thus, we get
E = 2.592 x 106 J ~ 2.6 MJ