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Question

a stone drops from the edge of the roof. it crosses a window 2 m long in 0.1 s. how much time does the stone take to reach the lower end of window from roof.

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Solution

Let v be the velocity of the stone at the upper end.s = vt + 12gt22 = v(0.1) +0.5×10×0.01 2-0.05 = v(0.1)1.95/0.1 = vv = 19.5 m/sinitial velocity when stone is dropped is 0v2-u2 = 2gs'where s' is the height distance between the edge and upper end of the window19.52 = 2×10×s's' = 19.01 mtotal distance travelled = 19.01+2 = 21.01 mtime taken is t21.01 = 1210t2t = 2.04 s

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