A stone falls from a cliff and travels 34.3 m in the laste second before it reaches the ground.Calculate the height of the cliff.

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Solution

Let the height of the cliff be ‘h’ and suppose it takes ‘n’ seconds to reach the ground.
So, in the n^th second it travels 34.3 m.
Using,
S_n = u + (a/2)(2n – 1)
=> 34.3 = 0 + (9.8/2)(2n – 1)
=> n = 4 s
Now, using,
S = ut + ½ at²
=> h = 0 + ½ × 9.8 × 4²
=> h = 78.4 m

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A stone falls from a cliff and travels 34.3 m in the laste second before it reaches the ground.Calculate the height of the cliff.

Let the height of the cliff be ‘h’ and suppose it takes ‘n’ seconds to reach the ground.So, in the nth second it travels 34.3 m.Using,Sn = u + (a/2)(2n – 1)=> 34.3 = 0 + (9.8/2)(2n – 1)=> n = 4 sNow, using,S = ut + ½ at2=> h = 0 + ½ × 9.8 × 42=> h = 78.4 m

Let the height of the cliff be ‘h’ and suppose it takes ‘n’ seconds to reach the ground.
So, in the n^th second it travels 34.3 m.
Using,
S_n = u + (a/2)(2n – 1)
=> 34.3 = 0 + (9.8/2)(2n – 1)
=> n = 4 s
Now, using,
S = ut + ½ at²
=> h = 0 + ½ × 9.8 × 4²
=> h = 78.4 m