Question

a stone is thrown vertically upwards at 15 m/s neglect friction due to the air what is the stones velocity after 2 seconds

Answer 1

Answer/Solution:

Given Values:

Initial velocity, u = 15 m/s

Time = 2 sec

Final velocity after 2 sec;
v = u + at
v = 15 + (-9.8) x 2 (Due to stone thrown upward, g = -9.8 m/s² )
v = 15 - 19.6
v = -4.6 m/s

Velocity after 2 sec = -4.6 m/s