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Finding Average Velocity

A stone throw...

Question

A stone thrown vertically upward such that when it reaches half of its height it has a velocity of 6.9m/s. What is the maximum height attained by stone?

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Solution

The initial velocity = u
Final at the top most point be v = 0.
Using, v²-u²=2as
0 - u²=2g(-s)
Given condition is at y = s/2, v = 6.9 m/s
So, 6.9²-2gs=2gs/2
Therefore, s = 6.9²/9.8
= 4.85 m

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