Question

A stunt man is to across a roof top jump horizontally off it, to land on the roof of next building. Before he attempts the jump, he wisely ask you to determine whether it is possible. Can he make the jump if his maximum speed is 4.5m/s.If the first building and the second building are at a horiontal distance of 6.2m. Also the first building is 4.8m higher than the other building?

Answer 1

As he jumps horizontally that means his horizontal velocity = v_x = 4.5 m/s

But he also falls a vertical distance of 4.8 m (Height difference between the two towers).

so, vertical velocity at the time of jump = v_y = 0

time taken to fall the vertical height = t = $\sqrt{\frac{2\times height}{g}}(from2ndequationofmotionafterputtingu=0)$

t = 0.9897 s

now horizontal distance to be covered in this time = v_x$\times$ time = 4.5 $\times$ 0.9897 = 4.45 m

which is less than the distance between the two buildings (6.2 m). Hence he should not make the jump.