A train is travelling with a speed of 90 km/hr.The brakes are applied so as to produce a uniform accelaration of -0.5 m/s.Find how far the train goes before it is brought to rest.

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Solution

Initial velocity, u = 90 km/h = 90(5/18) m/s = 25 m/s
Acceleration, a = -0.5 m/s²
Using,
v² = u² + 2as
=> 0 = 25² – 2(0.5)s
=> s = 625 m
The train travels 625 m before coming to rest.

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An express train going towards Delhi is travelling at a speed of $90 k m p h$ . Brakes are applied so as to produce a uniform acceleration of $- 0.5 m s^{- 2}$ . Find how far the train will go before it is brought to rest.

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A train is travelling with a speed of 90 km/hr.The brakes are applied so as to produce a uniform accelaration of -0.5 m/s.Find how far the train goes before it is brought to rest.

Initial velocity, u = 90 km/h = 90(5/18) m/s = 25 m/sAcceleration, a = -0.5 m/s2Using,v2 = u2 + 2as=> 0 = 252 – 2(0.5)s=> s = 625 mThe train travels 625 m before coming to rest.

Initial velocity, u = 90 km/h = 90(5/18) m/s = 25 m/s
Acceleration, a = -0.5 m/s²
Using,
v² = u² + 2as
=> 0 = 25² – 2(0.5)s
=> s = 625 m
The train travels 625 m before coming to rest.