a train starting from rest attains a velocity of 20m/sec in 2 min assuming that the acceleration is uniform find the acceleration and the distance traveled by the train while it attained its velocity
here,
u = 0
v = 20 m/s
t = 2 min = 120 secs.
thus, acceleration will be
a = (v-u) / t
or
a = 20/120 = 0.166666 m/s2
the distance travelled will be
s = (v2 - u2) / 2a [from v2-u2 = 2as]
thus,
s = 202 - 0 / (2x0.166)
or
s = 1204.8 m