Question

ABCD is a parallelogram and 'O' is the midpoint of AB.If area of parallelogram is 154 sq.cm'then what is the area of triangle DOC?

Answer 1

Since triangle DOC and parallelogram ABCD have common base DC and between same parallels AB and CD, then​


$$\begin{gathered} ar.(∆DOC)=\frac{1}{2}ar.(|{|}^{gm}ABCD) \\ \Rightarrow ar.(∆DOC)=\frac{1}{2}\times 154=77c{m}^2 \end{gathered}$$