What should be taken away from 3x2 minus- 4y2- 5xy - 20 to obtain minus- x2 minus- y2 - 6xy- 20-

Let pbe the required term.(3x2âˆ’ 4y2 + 5xy + 20) âˆ’ p = âˆ’x2 âˆ’ y2 + 6xy + 20p =(3x2 âˆ’ 4y2 + 5xy +20) âˆ’ (âˆ’ x2 âˆ’ y2+ 6xy + 20)= 3x2 âˆ’ 4y2 + 5xy +20 ...

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Byju's Answer

Standard VI

Mathematics

Coefficient

What should b...

Question

What should be taken away from 3x² − 4y²+ 5xy + 20 to obtain
− x² − y²+ 6xy+ 20?

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Solution

Let pbe the required term.
(3x²âˆ’ 4y² + 5xy + 20) âˆ’ p = âˆ’x² âˆ’ y² + 6xy + 20
p =(3x² âˆ’ 4y² + 5xy +20) âˆ’ (âˆ’ x² âˆ’ y²+ 6xy + 20)
= 3x² âˆ’ 4y² + 5xy +20 + x² + y² âˆ’ 6xy âˆ’20
= 3x² + x²âˆ’ 4y²+ y² + 5xy âˆ’ 6xy + 20 âˆ’20
= 4x² âˆ’ 3y² âˆ’ xy

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What should be taken away from 3x2 − 4y2+ 5xy + 20 to obtain− x2 − y2 + 6xy+ 20?

What should be taken away from 3x² − 4y²+ 5xy + 20 to obtain
− x² − y²+ 6xy+ 20?